
Operand 1 specifies the even register of an even-odd consecutive
pair of general purpose registers. For
instance R4 would represent registers 4 and 5, while R8 would represent
registers 8 and 9. SLDL is used to shift the 64 bits in the even-odd pair as if they
comprised a single register. The shift
is to the left. The number of bits that
are shifted is indicated by Operand 2.
The second operand address is not
used to address data; instead, the base/displacement address is computed and
the rightmost 6 bits are treated as a binary integer which represents the
number of bits to be shifted. We will
call this value the shift factor.
This leads to two distinct ways of coding the shift factor:
1) Directly - The shift factor
is coded as a displacement. Consider
the example below.
SLDL R8,5
In the above shift, the
second operand, 5, is treated as a base/displacement address where 5 is the
displacement and the base register is omitted.
The effective address is 5. (See Explicit
Addressing.) When represented as an
address the rightmost 6 bits still represent the number 5, and so the bits in
registers 8 and 9 are shifted to the left by 5 bits.
2) Indirectly - The shift
factor is placed in a register and the register is mentioned as the base
register in the base/displacement address.
L R5,FACTOR PUT SHIFT FACTOR IN REG
SLDL R8,0(R5) NOW SHIFT INDIRECTLY
...
FACTOR DC F8 SHIFT FACTOR IS 8 BITS
In this case, the effective
address is computed by adding the contents of base register 5 (which is 8),
with the displacement of 0. The
effective address is again 8, and the rightmost 6 bits of this address indicate
that the shift factor is 8.
Each method has its uses.
The direct method is useful in situations where the number of bits you
want to shift is fixed. Coding directly
allows you to look at the instruction to determine the shift factor. On the other hand, the indirect method
allows the shift factor to be determined while the program is executing. If the shift factor cannot be determined
until the program is running, the indirect method must be used.
When shifting logically,
bits shifted out on the left are lost, while 0s replace bits on the right.
Consider the following instruction.
SLDL R8,6
This instruction represents
a left shift of registers 8 and 9 using
a shift factor of 6. The shift factor
has been coded directly. As a result, 6
bits, 111100, are shifted out of the register on the left. Vacated bit positions on the right are
replace by 0s. This is illustrated in
the diagram below.

This instruction has an RS
format but the 4 low-order bits of the second byte are unused.
Some Unrelated SLDLs
R4 =
B11110000111111111111111111111111
R5 =
B00000000000000000000000000001111
SLDL
R4,1 R4 =
B11111111111111111111111111111110
R5 =
B00000000000000000000000000011110
SLDL
R4,2 R4 =
B11111111111111111111111111111100
R5 = B00000000000000000000000000111100
SLDL
R4,31 R4 =
B10000000000000000000000000000111
R5 =
B10000000000000000000000000000000
SLDL
R4,32 R4 =
B00000000000000000000000000001111
R5 =
B00000000000000000000000000000000
SLDL
R4,4 R4 =
B00001111111111111111111111110000
R5 =
B00000000000000000000000011110000
L
R9,=F3
SLDL
R4,0(R9) R4 = B10000111111111111111111111111000
R5 = B00000000000000000000000001111000
L
R3,=F5
SLL
R4,0(R3) R4 =
B00011111111111111111111111100000
R5 =
B00000000000000000000000111100000